Free Algebra Tutorials!
Try the Free Math Solver or Scroll down to Tutorials!

 Depdendent Variable

 Number of equations to solve: 23456789
 Equ. #1:
 Equ. #2:

 Equ. #3:

 Equ. #4:

 Equ. #5:

 Equ. #6:

 Equ. #7:

 Equ. #8:

 Equ. #9:

 Solve for:

 Dependent Variable

 Number of inequalities to solve: 23456789
 Ineq. #1:
 Ineq. #2:

 Ineq. #3:

 Ineq. #4:

 Ineq. #5:

 Ineq. #6:

 Ineq. #7:

 Ineq. #8:

 Ineq. #9:

 Solve for:

 Please use this form if you would like to have this math solver on your website, free of charge. Name: Email: Your Website: Msg:

# Factoring by Grouping

 WHAT TO DO: HOW TO DO IT: Given a trinomial of type ax2 + bx + c that has no common factor, where signs may be positive or negative. Separate the signs from the coefficients. [Read Â± as + or - ] Read the â€œclues of the signsâ€. Find product of first and last coefficients. This is the grouping number (GN) GN AÂ·C = P Find all possible factors of GN = P whose sum or difference is B (depending on the sign before C.) + sum or - difference P = rÂ·s , r > s(r + s) = B   (r - s) = B Example: Given: 10x2 + 11x - 6 GN 10Â·6 = 60 The last sign is â€œ−â€ so find the pair of factors of 60 that has a difference of 11. The largest factor of the pair gets middle sign, + + 15 and - 4 The trinomial can be arranged in four terms using these values as coefficients of x, grouped 2 Ã— 2 10x2 + 15x − 4x − 6 Factor common factor from each group: 5x(2x + 3) − 2(2x + 3) Find common term in ( ), factor: (5x − 2)(2x + 3) Check by FOIL method. Always CheckÂ·

 All Right Reserved. Copyright 2005-2018